Eintext.htm

Paragraphs 1 and 2 apply to Einstein's classic simultanous event observers of directions A and B while Paragraphs 3 and 4 apply the same parameters to directions A, B, C, D, E, and F.

Paragraph 1

This is a filler page until I can get the final copy up and
running.( I haven't gotten back to my original discussion yet so
while I am still fine tuning that, just consider this - in
Einstein's premise of simultaneous events, he dismisses rotation
(__K and K' as devoid of rotation__) and then goes on to use
Lorentz formula's to solve his dilemma. Lorentz formulas are EM
based and as such are ROTATION dependent. What Einstein appears
to have shown is the Doppler effect of light as seen by a moving
observer. Special theory is a Doppler theory of light - had
Einstein used the energy of the light seen by M' from A and B and
calculated it against M's velocity away from A and toward B, M'
could have determined that the lightning strikes at points A and
B were, in fact, simultaneous and of equal intensity, period.

Paragraph 2

Basically, just consider M (stationary) and M' (moving) as Einstein's two observers of simultaneous events. If they are exactly at the same distance (point M) from A and B at the same time that the light arrives from A and B, then M and M' will see the light at the SAME time. Or should I say begin to see the light at the same time. If M and M' had seen only ONE wavelength of one frequency of light, they would have both begun to see the light at the same time (Spectrum), but because it is a longitudinal wave on CDM particles, M' who is moving toward B would pass through the B wave before either A or B wave finishes at M. BUT M' would also see A wave longer since he is moving away from it. Also M' would see a blue shifted wave (compressed) from B and a red shifted (expanded) wave from A compared to M who would see identical A and B waves. M and M' begin to see the A and B waves AT the same time, M' just finishes the spectrum of B sooner because he has now moved toward it. And thus is no longer equal distance from A and B.

M' could use Doppler shift formulas using his velocity to calculate back determining that A and B really were simultaneous events, and Newton's law of relativity holds in ALL frames of reference.

Anyone interested (or wants to explain) in how M", MT, and I are positioned, moving or otherwise see the light of A and B, please e-mail dew@deskmedia.com me your explanation and I will addend it to this page. (Yes, I think I have the answers and will be presenting them at a later date but I was trying to avoid confusion by not adding them at this time.)

Copyright September 15, 1998 - Dewey Birkhofer Return to Homepage or Return to Cold Dark

For 3 dimensions, consider M (stationary) and M' (moving) as Einstein's two observers of simultaneous events. If they are exactly at the same distance (at point M) from A, B, C, D, E, and F at the same time that the light arrives from A, B, C, D, E, and F, then M and M' will see the light at the SAME time from all 6 directions. Or should I say begin to see the light at the same time. If M and M' had seen only ONE wavelength of one frequency of light, they would have both begun to see the light at the same time (Spectrum 2), but because it is a longitudinal wave on CDM particles, M' who is moving toward B would pass through the B wave before either A or B wave finishes at M. BUT M' would also see A wave longer since he is moving away from it. Also M' would see a blue shifted wave (compressed) from B and a red shifted (expanded) wave from A compared to M who would see identical A, B, C, D, E, and F waves while M' would see identical (simultaneous) C, D, E, and F waves. M and M' begin to see the A, B, C, D, E, and F waves AT the same time, M' just finishes the spectrum of B sooner because he has now moved toward it and finish seeing A, C, D, E, and F waves later than M. And thus is no longer equal distance from A and B. But since M' sees C, D, E, and F as identical, M' would be obligated to conclude that frames in vertical and lateral dimension are of the same "time" dimension and therefore, simultaneous frames as M concluded. Once M' adjusted for his or her velocity, M' would also be able to conclude all events lateral, vertical and horizontal were (are) simultaneous events. Time did not compress in the B direction anymore that it appeared to dilate in the A direction, only the video image (wavelength) compresses or expands respectively when moving toward or away from an image (light) source.

Paragraph 4

As can be seen in Spectrum 2, M' spectra of C,D,E, and F waves are expanded which appear as left shifting and of decreasing intensity since from the time when the light is initially sensed, M' is actually (in a tangential sense) moving away from C, D, E, and F sources. Since M' is moving directly toward B and away from A, these are SPECIAL conditions which would maximize Doppler wave shifting which gives an apparent time shift. However, using proper Doppler shift formula, all events can be shown to be simultaneous to ALL observers. I have no objection to using Special theory for these special circumstances, but these shifts are WAVE shifts and as correctly suspected and proposed by Lorentz, do NOT apply to Length shifts (only VIDEO image which can be processed shrinks, not the ACTUAL length of the moving object.)

Speculation of a sort

Of course, while length is a measure of "static" volume, Mass appears to be a measure of "dynamic" volume. (Collision with a ball rolling at 5 km per hour is much less destressful than colliding with a sphere rolling at 5 million km per hour since the 2nd sphere has acquire "kinetic" mass. But as mass approaches the speed of light, it would appear to be to experience a coeffiecient of drag based on Ether dynamics (i.e. according to the rotational velocity of the ether) and therefore the Mass increase is real due to coefficient of ether drag while the length contraction is not real but a contraction of the video (wave) signal of the image at high velocities.