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Then, we can draw a picture of the wedge with appropriate stresses on each face and use equilibrium equations to relate the stresses.
To write equilibrium equations, we must multiply the stresses by the area on which they act to get forces. Assuming the area of the cut face is A, the horizontal face of the wedge will have an area of A sinq and the vertical face will have an area of A cosq.
Now, considering equilibrium in the x’ direction
SFx’ = 0 : sx’A - (sx Acosq) cosq - (txy Acosq) sinq - (txy Asinq) cosq - (sy Asinq) sinq = 0
Rearranging and dividing out the common A, we get
sx’ = sx cos2q + 2 txy sinq cosq + sy sin2q
Using the following trig identities, we can rewrite this equation
cos2q = (1 + cos2q)/2 sin2q = (1 - cos2q)/2 2sinq cosq = sin2q
sx’ = (sx + sy)/2 + ((sx - sy)/2) cos2q + txy sin2q
If we consider the y’ direction,
SFy’ = 0
tx’y’ A + (sx Acosq) sinq - (txy Acosq) cosq + (txy Asinq) sinq - (sy Asinq) cosq = 0
Rearranging and dividing out A, we get |

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Lecture #24, page 2 Back Lecture #24, page 3 |